Horse and cart problem
This is the topic Horse and cart problem which explain the one of the important illustration of Newton’s third law of motion.
But before to learn the topic Horse and cart problem students must know, Newton’s third law of motion. To get the notes on Newton’s third law of motion click here-
Horse and cart problems –
Suppose a cart is connected with a horse by a light inextensible string. When horse start to walk horse press the ground F ( action ) with their feet in the slightly backward direction and ground exert an equal reaction R , as shown in figure . then R has two component H = R cosϴ in horizontal direction and V= R sinϴ in vertical direction . V balance the weight of the horse and H makes the horse to move in forward direction . While pulling the cart produces a tension T in the string .
If H > T then cart starts moving in the forward direction with acceleration ‘a’ .
Net force acting on the horse = H-T= ma.( where m is the mass of the horse)……………..(i)
If f is the frictional force between tyre of cart and ground then for cart we can write
T-F= Ma ( M is the mass of the cart ) …………………………(ii)
From equations (i) and (ii) we get ,
H-f = ( M+m ) a ;
So, acceleration a = H-f/ (M+m ) ;
The whole system will move if H>f ;